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C++ remove_copy_if()

C++算法remove_copy_if()

C++算法 remove_copy_if()函数用于将[first,last)范围内的所有元素复制到该范围从结果开始,除了那些pred返回true的元素,而不会干扰其余元素的顺序。
此功能无法更改容器的大小。
它将迭代器返回到范围的新末端。 删除是稳定的,表示未删除的元素的相对顺序保持不变。

语法

template <class InputIterator, class OutputIterator, class UnaryPredicate>
OutputIterator remove_copy_if (InputIterator first, InputIterator last, 
OutputIterator result, UnaryPredicate pred);

参数

first: 前向迭代器,指向要删除元素范围内第一个元素的位置。
last: 前向迭代器,指向要删除元素范围内最后一个元素之后的位置。
result: 一个输出迭代器,指向要删除元素的范围的初始位置。
pred : 必须替换元素的值。

返回值

一个向前的迭代器,指向复制范围的新结束位置(末尾),该末尾包括[first,last)中的所有元素,但pred将返回true的元素除外。

复杂性

复杂度在[first,last)范围内是线性的: 将pred应用于每个元素,并对未删除的元素执行赋值操作。

数据竞争

访问[first,last)范围内的对象。
结果和返回值之间的范围内的对象被更改。

异常

如果pred,元素分配或迭代器上的任何操作抛出异常,则此函数将引发异常。
请注意,无效的参数会导致未定义的行为。

示例1

让我们看一个简单的示例来演示e使用remove_copy_if():
#include <algorithm>
#include <iostream>
#include <vector>
#include <iterator>
using namespace std;
int main() {
  vector<int> v = { 2,1,3,4,5,7,6,9,8};
  remove_copy_if(v.begin(), v.end(),
    ostream_iterator<int>(cout, ","),
    [](int x) { return x%2 != 0; });
    
    return 0;
}
输出:
2,4,6,8,

示例2

让我们看另一个简单的示例:
#include <vector> 
#include <algorithm> 
#include <iostream> 
using namespace std; 
  
bool IsOdd(int i) { 
return ((i % 2) != 0); 
} 
  
// Function to remove from v1 result vector is v2 
void remove_copy_ifDemo(vector <int> &v1, vector<int> &v2) 
{ 
    remove_copy_if(v1.begin(), v1.end(), v2.begin(), IsOdd); 
} 
  
// Function to print content of vector 
void print(vector<int>&v) 
{ 
    int len = v.size(); 
    for (int i = 0; i < len; i++) 
        cout << v[i] << " "; 
    cout << endl; 
} 
   
int main() 
{ 
    // declare vector v1, v2 
    vector <int> v1, v2(10); 
      
    // push data in vector  
    for(int i = 10; i <= 20; i++) 
        v1.push_back(i); 
      
    cout << "elements of v1 before remove_copy: "; 
    print(v1); 
  
remove_copy_ifDemo(v1,v2); 
      
    cout << "elements of v1 after remove_copy: "; 
    print(v1); 
      
cout << "After removing Odd Numbers from v1"
            " copy result in vector v2" <<endl; 
    print(v2); 
  
return 0; 
}
输出:
elements of v1 before remove_copy: 10 11 12 13 14 15 16 17 18 19 20 
elements of v1 after remove_copy: 10 11 12 13 14 15 16 17 18 19 20 
After removing Odd Numbers from v1 copy result in vector v2
10 12 14 16 18 20 0 0 0 0

示例3

让我们看另一个简单的示例:
#include <iostream>
#include <vector>
#include <algorithm>
#include <functional>
using namespace std;
int main()
{
    const int MAX_ELEMENTS = 8 ;
    // Define a template class vector of integers
    typedef vector<int > IntVector ;
    //Define an iterator for template class vector of integer
    typedef IntVector::iterator IntVectorIt ;
    //vector containing numbers
    IntVector Numbers(MAX_ELEMENTS), Result(MAX_ELEMENTS) ;
    IntVectorIt start, end, it, last, resultIt ;
    //Initialize vector Numbers
    Numbers[0] = 10 ;
    Numbers[1] = 20 ;
    Numbers[2] = 10 ;
    Numbers[3] = 15 ;
    Numbers[4] = 12 ;
    Numbers[5] = 25 ;
    Numbers[6] = 30 ;
    Numbers[7] = 10 ;
    start = Numbers.begin() ;   // location of first
                                // element of Numbers
    end = Numbers.end() ;       // one past the location
                                // last element of Numbers
    resultIt = Result.begin() ; // location of first
                                // element of Result
    // print content of Numbers
    cout << "Numbers { " ;
    for(it = start; it != end; it++)
        cout << *it << " " ;
    cout << " }\n" << endl ;
    // copy all elements from Numbers to Result
    // skipping any item that >= 25
    last = remove_copy_if(start, end, resultIt,
                          bind2nd(greater_equal<int>(), 25)) ;
    //print number of elements copied to Result
    cout << "Total number of elements copied to Result = "
        << last-resultIt << endl ;
    start = Result.begin() ;   // location of first
                                // element of Result
    end = Result.end() ;       // one past the location
                               // last element of Result
    // print content of Result
    cout << "Result { " ;
    for(it = start; it != end; it++)
        cout << *it << " " ;
    cout << " }\n" << endl ;
    
    return 0;
}
输出:
Numbers { 10 20 10 15 12 25 30 10  }
Total number of elements copied to Result = 6
Result { 10 20 10 15 12 10 0 0  }

示例4

让我们看另一个简单的示例:
#include <vector>
#include <algorithm>
#include <iostream>
using namespace std;
bool greathan(int value)
{ return value >7;}
 
int main(void)
{
// vector container
vector <int> vec1, vec2(14);
// vector iterator
vector <int>::iterator Iter1, Iter2, new_end;
int i, j;
// push data in range
for(i = 0; i <= 10; i++)
vec1.push_back(i);
for(j = 0; j <= 2; j++)
vec1.push_back(5); 
// print the data
cout<<"The original vec1 vector data: ";
for(Iter1 = vec1.begin(); Iter1 != vec1.end(); Iter1++)
cout<<*Iter1<<" ";
cout<<endl;
// randomly shuffle the data
random_shuffle(vec1.begin(), vec1.end());
cout<<"\nThe original vec1 vector data randomly shuffled: ";
for(Iter1 = vec1.begin(); Iter1 != vec1.end(); Iter1++)
cout<<*Iter1<<" ";
cout<<endl;
// remove elements with a value greater than 7
new_end = remove_copy_if(vec1.begin(), vec1.end(), vec2.begin(), greathan);
cout<<"\nAfter the remove_copy_if() operation, the vec1 vector is left unchanged as: ";
for(Iter1 = vec1.begin(); Iter1 != vec1.end(); Iter1++)
cout<<*Iter1<<" ";
cout<<endl;
cout<<"\nvec2 vector is a copy of vec1 vector with values greater than 7 removed: ";
for(Iter2 = vec2.begin(); Iter2 != new_end; Iter2++)
cout<<*Iter2<<" ";
cout<<endl;
return 0;
}
输出:
The original vec1 vector data: 0 1 2 3 4 5 6 7 8 9 10 5 5 5 
The original vec1 vector data randomly shuffled: 4 10 5 5 0 5 5 1 6 9 3 7 8 2 
After the remove_copy_if() operation, the vec1 vector is left unchanged as: 4 10 5 5 0 5 5 1 6 9 3 7 8 2 
vec2 vector is a copy of vec1 vector with values greater than 7 removed: 4 5 5 0 5 5 1 6 3 7 2

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