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C++ Set swap()

C++ " swap()函数用于交换(或交换)两个集合的内容,但是两个集合必须是相同的类型。

语法

void swap (set& x);

参数

x : Set 容器以与之交换内容。

返回值

复杂度

常量。

迭代器有效性

全部在两个集合容器中引用元素的引用,迭代器和指针仍然有效,但是现在正在引用另一个集合容器中的元素,并在其中进行迭代。

数据竞争

容器和x均被修改。

异常安全性

如果引发异常,则对容器没有影响。

示例1

让我们看一下将一组元素交换为另一组的简单示例:
#include <iostream>
#include <set>
using namespace std;
int main(void) {
   set<int> m1 = {1,2,3,4,5};
   set<int> m2;
   m2.swap(m1);
   cout << "Set contains following elements" << endl;
   for (auto it = m2.begin(); it != m2.end(); ++it)
      cout << *it<< endl;
   return 0;
}
输出:
Set contains following elements
1
2
3
4
5
在上面的示例中,集合m1具有五个元素,而m2为空。当您将m1交换为m2时,m1的所有元素都将交换为m2、

示例2

让我们看一个简单的示例来交换两个集合的内容:
#include <iostream>
#include <set>
using namespace std;
 int main () {
   int myints[] = {10,20,30,40,50,60};
   set<int> first (myints,myints+3);
   set<int> second (myints+3,myints+6);  
   first.swap(second);
   cout << "first set contains:";
   for (set<int>::iterator it = first.begin(); it!=first.end(); ++it)
      cout << ' ' << *it;
   cout << '\n';
   cout << "second set contains:";
   for (set<int>::iterator it = second.begin(); it!=second.end(); ++it)
      cout << ' ' << *it;
   cout << '\n';
   return 0;
}
输出:
first set contains: 40 50 60
second set contains: 10 20 30

示例3

让我们看一个简单的示例来交换两组内容:
#include<iostream>
#include<set>
using namespace std;
 
int main()
{
    // Take any two sets
    set<char> set1, set2;
    
    set1 = {'a','b','c','d'}; 
    set2 = {'x','y','z'};
 
    // Swap elements of sets
    swap(set1, set2);
 
    // Print the elements of sets
    cout << "set1:\n";
    for (auto it = set1.begin(); it != set1.end(); it++)
        cout << "\t" << *it<< '\n';
 
    cout << "set2:\n";
    for (auto it = set2.begin(); it != set2.end(); it++)
        cout << "\t" << *it<< '\n';
 
    return 0;
}
输出:
set1:
  x
  y
  z
set2:
  a
  b
  c
  d
在上面的示例中,另一种形式的swap()函数用于交换两个集合的内容。

示例4

让我们看看简单的例子:
#include <set>  
#include <iostream>  
  
int main( )  
{  
   using namespace std;  
   set <int> s1, s2, s3;  
   set <int>::iterator s1_Iter;  
  
   s1.insert( 10 );  
   s1.insert( 20 );  
   s1.insert( 30 );  
   s2.insert( 100 );  
   s2.insert( 200 );  
   s3.insert( 300 );  
  
   cout << "The original set s1 is:";  
   for ( s1_Iter = s1.begin( ); s1_Iter != s1.end( ); s1_Iter++ )  
      cout << " " << *s1_Iter;  
   cout   << "." << endl;  
  
   // this is the member function version of swap  
   s1.swap( s2 );  
  
   cout << "After swapping with s2, list s1 is:";  
   for ( s1_Iter = s1.begin( ); s1_Iter != s1.end( ); s1_Iter++ )  
      cout << " " << *s1_Iter;  
   cout  << "." << endl;  
  
   // this is the specialized template version of swap  
   swap( s1, s3 );  
  
   cout << "After swapping with s3, list s1 is:";  
   for ( s1_Iter = s1.begin( ); s1_Iter != s1.end( ); s1_Iter++ )  
      cout << " " << *s1_Iter;  
   cout   << "." << endl;  
}  
输出:
The original set s1 is: 10 20 30.
After swapping with s2, list s1 is: 100 200.
After swapping with s3, list s1 is: 300.

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