Java在字符串中查找重复的字符
在此程序中，我们需要查找字符串中的重复字符。
责任重大
要从字符串中查找重复的字符，我们计算字符串中每个字符的出现次数。如果count大于1，则表示字符在字符串中具有重复的条目。在上面的示例中，以绿色突出显示的字符是重复字符。
算法
步骤1: 开始
步骤2: 定义字符串string1 ="Great responsibility"
步骤3: 定义 count
步骤4: 将string1转换为char[]字符。
步骤5: 打印"Duplicate characters in a given string: "
步骤6: SET i =0。直到i重复STEP 7至STEP 11
STEP 7: SET count = 1
步骤8: SET j = i + 1。直到j将步骤8重复到步骤10
步骤9: IF(string[i] == string[j] && string[i]!='')
则then
count = count + 1
string[j] = 0
步骤10: j = j + 1
步骤11: i = i + 1
步骤12: IF(count> 1 && string[i]!= 0)，然后打印字符串[i]
步骤13: END
程序:
public class DuplicateCharacters {
public static void main(String[] args) {
String string1 = "Great responsibility";
int count;
//Converts given string into character array
char string[] = string1.toCharArray();
System.out.println("Duplicate characters in a given string: ");
//Counts each character present in the string
for(int i = 0; i <string.length; i++) {
count = 1;
for(int j = i+1; j <string.length; j++) {
if(string[i] == string[j] && string[i] != ' ') {
count++;
//Set string[j] to 0 to avoid printing visited character
string[j] = '0';
}
}
//A character is considered as duplicate if count is greater than 1
if(count > 1 && string[i] != '0')
System.out.println(string[i]);
}
}
}
输出:
Duplicate characters in a given string:
r
e
t
s
i
