Java教程

Java查找给定矩阵的转置

在此程序中,我们需要找到给定矩阵的转置并打印结果矩阵。

矩阵的转置

可以通过将行与列互换来找到矩阵的转置,也就是说,原始矩阵的行将成为新矩阵的列。同样,原始矩阵中的列将成为新矩阵中的行。该操作可以表示为:
Java查找给定矩阵的转置的程序
如果原始矩阵的尺寸为2×3,则新的转置矩阵的尺寸将为3×2。
[ AT ]<sub>ij</sub>=[ A ]<sub>ji</sub>

算法

步骤1: START 步骤2: 定义rows,cols 步骤3: 初始化矩阵a[][] = {{1,2,3},{4,5,6},{7,8,9}} 步骤4: rows= a.length 步骤5: cols = a[0].length 步骤6: t[][] = [cols][rows] 步骤7: 直到将i < cols
////for(i = 0; i < cols; i++) 重复步骤8至步骤9
步骤8: 重复步骤9,直到j < rows
////for(j = 0; j < rows; j++)
步骤9: t[i][j] = a[j][i] 步骤10: 打印"给定矩阵的转置" 步骤11: 直到将i < cols
////for(i = 0; i < cols; i++) 重复步骤12至步骤14
步骤12: 重复步骤13,直到j < rows
////for(j = 0; j < rows; j++)
步骤13: 打印t[i][j] 步骤14: 打印新行 STEP 15: END

程序

public class Transpose
{
    public static void main(String[] args) {
        int rows, cols;
        //Initialize matrix a
          int a[][] = {
            {1, 2, 3},
            {4, 5, 6},
            {7, 8, 9}
        };
        //Calculates number of rows and columns present in given matrix
          rows = a.length;
        cols = a[0].length;
        //Declare array t with reverse dimensions
        int t[][] = new int[cols][rows];
        //Calculates transpose of given matrix
        for(int i = 0;i <cols;i++){
            for(int j = 0;j <rows;j++){
                //Converts the row of original matrix into column of transposed matrix
                t[i][j] = a[j][i];
            }
        }
        System.out.println("Transpose of given matrix: ");
        for(int i = 0;i <cols;i++){
            for(int j = 0;j <rows;j++){
                System.out.print(t[i][j] + " ");
            }
            System.out.println();
        }
    }
}
输出:
Transpose of given matrix
1 4 7
2 5 8
3 6 9
昵称: 邮箱:
Copyright © 2022 立地货 All Rights Reserved.
备案号:京ICP备14037608号-4