C++ Math lround()
C++ Math lround()
此函数用于舍入给定值并将其转换为长整数。
语法
假设数字为" x"。语法为:
long int lround(data_type x);
参数
x : 该值可以是float或double。
返回值
它返回x的舍入值。该函数的返回类型为long int。
示例1
让我们看一个使用lround()函数的简单示例
#include <iostream>
#include<math.h>
using namespace std;
int main()
{
float x=2.3;
double y=-12.6;
float z=23.6;
std::cout << "The value of x is : " <<x<< std::endl;
std::cout << "The value of y is : " <<y<< std::endl;
std::cout << "The value of z is : " <<z<< std::endl;
cout<<"Rounded value of x is : "<<lround(x)<< std::endl;
cout<<"Rounded value of y is : "<<lround(y)<< std::endl;
cout<<"Rounded value of z is : "<<lround(z)<< std::endl;
return 0;
}
输出:
The value of x is : 2.3
The value of y is :-12.6
The value of z is : 23.6
Rounded value of x is : 2
Rounded value of y is :-13
Rounded value of z is : 24
