C++ 寻找矩阵转置的程序-立地货

查找矩阵转置的 C++ 程序

这个程序从用户那里获取一个 r*c 阶矩阵并计算矩阵的转置。

要理解此示例，您应该了解以下C++ 编程主题:

C++ 数组

C++ 多维数组

在这个程序中，用户被要求输入行数和列数。本程序中 rows和 columns的值应小于10、

然后，要求用户输入矩阵的元素。

程序计算矩阵的转置并将其显示在屏幕上。

示例: 求矩阵的转置

#include <iostream>
using namespace std;
int main() {
   int a[10][10], transpose[10][10], row, column, i, j;
   cout << "Enter rows and columns of matrix: ";
   cin >> row >> column;
   cout << "\nEnter elements of matrix: " << endl;
   // Storing matrix elements
   for (int i = 0; i < row; ++i) {
      for (int j = 0; j < column; ++j) {
         cout << "Enter element a" << i + 1 << j + 1 << ": ";
         cin >> a[i][j];
      }
   }
   // Printing the a matrix
   cout << "\nEntered Matrix: " << endl;
   for (int i = 0; i < row; ++i) {
      for (int j = 0; j < column; ++j) {
         cout << " " << a[i][j];
         if (j == column-1)
            cout << endl << endl;
      }
   }
   // Computing transpose of the matrix
   for (int i = 0; i < row; ++i)
      for (int j = 0; j < column; ++j) {
         transpose[j][i] = a[i][j];
      }
   // Printing the transpose
   cout << "\nTranspose of Matrix: " << endl;
   for (int i = 0; i < column; ++i)
      for (int j = 0; j < row; ++j) {
         cout << " " << transpose[i][j];
         if (j == row-1)
            cout << endl << endl;
      }
   return 0;
}

输出

Enter rows and columns of matrix: 2
3
Enter elements of matrix:
Enter element a11: 1
Enter element a12: 2
Enter element a13: 9
Enter element a21: 0
Enter element a22: 4
Enter element a23: 7
Entered Matrix:
1  2  9
0  4  7
Transpose of Matrix:
1  0
2  4
9  7