示例 1: 将二进制转换为八进制的程序
在这个程序中,我们将首先将二进制数转换为十进制数。然后,十进制数转换为八进制数。
#include <iostream> #include <cmath> using namespace std; int convertBinarytoOctal(long long); int main() { long long binaryNumber; cout << "Enter a binary number: "; cin >> binaryNumber; cout << binaryNumber << " in binary = " << convertBinarytoOctal(binaryNumber) << " in octal "; return 0; } int convertBinarytoOctal(long long binaryNumber) { int octalNumber = 0, decimalNumber = 0, i = 0; while(binaryNumber != 0) { decimalNumber += (binaryNumber%10) * pow(2,i); ++i; binaryNumber/=10; } i = 1; while (decimalNumber != 0) { octalNumber += (decimalNumber % 8) * i; decimalNumber /= 8; i *= 10; } return octalNumber; }
输出
Enter a binary number: 10001 10001 in binary = 21 in octal
用户输入的二进制数传递给
convertBinaryToOctal()
函数。并且,此函数将数字转换为八进制并返回到
main()
函数
示例 2: 将八进制转换为二进制的程序
在这个程序中,首先将八进制数转换为十进制数。然后,将十进制数转换为二进制数。
#include <iostream> #include <cmath> using namespace std; long long convertOctalToBinary(int); int main() { int octalNumber; cout << "Enter an octal number: "; cin >> octalNumber; cout << octalNumber << " in octal = " << convertOctalToBinary(octalNumber) << "in binary"; return 0; } long long convertOctalToBinary(int octalNumber) { int decimalNumber = 0, i = 0; long long binaryNumber = 0; while(octalNumber != 0) { decimalNumber += (octalNumber%10) * pow(8,i); ++i; octalNumber/=10; } i = 1; while (decimalNumber != 0) { binaryNumber += (decimalNumber % 2) * i; decimalNumber /= 2; i *= 10; } return binaryNumber; }
输出
Enter an octal number: 54 54 in octal = 101100
用户输入的八进制数传递给
convertOctalToBinary()
函数。并且,此函数将数字转换为二进制并返回
main()
函数