Python 将列表中的指定位置的两个元素对调
Python 将列表中的指定位置的两个元素对调的例子
定义一个列表,并将列表中的指定位置的两个元素对调。
例如,对调第一个和第三个元素:
对调前 : List = [22, 65, 33, 90], pos1 = 1, pos2 = 3
对调后 : [33, 65, 22, 90]
# Filename : example.py
# DateTime : 2020-07-20
# author by : www.lidihuo.com
def swapPositions(list, pos1, pos2):
list[pos1], list[pos2] = list[pos2], list[pos1]
return list
List = [22, 65, 33, 90]
pos1, pos2 = 1, 3
print(swapPositions(List, pos1-1, pos2-1))
以上实例输出结果为:
# Filename : example.py
# DateTime : 2020-07-20
# author by : www.lidihuo.com
def swapPositions(list, pos1, pos2):
first_ele = list.pop(pos1)
second_ele = list.pop(pos2-1)
list.insert(pos1, second_ele)
list.insert(pos2, first_ele)
return list
List = [23, 65, 19, 90]
pos1, pos2 = 1, 3
print(swapPositions(List, pos1-1, pos2-1))
以上实例输出结果为:
# Filename : example.py
# DateTime : 2020-07-20
# author by : www.lidihuo.com
def swapPositions(list, pos1, pos2):
get = list[pos1], list[pos2]
list[pos2], list[pos1] = get
return list
List = [23, 65, 19, 90]
pos1, pos2 = 1, 3
print(swapPositions(List, pos1-1, pos2-1))
以上实例输出结果为: