C语言指针

int n = 10; 
int* p = &n; // Variable p of type pointer is pointing to the address of the variable n of type integer. 

int *a;//pointer to int
char *c;//pointer to char

#include<stdio.h>
int main(){
int number=50;  
int *p;    
p=&number;//stores the address of number variable  
printf("Address of p variable is %x \n",p); // p contains the address of the number therefore printing p gives the address of number.   
printf("Value of p variable is %d \n",*p); // As we know that * is used to dereference a pointer therefore if we print *p, we will get the value stored at the address contained by p.  
return 0;
}  

Address of number variable is fff4
Address of p variable is fff4
Value of p variable is 50

int arr[10];
int *p[10]=&arr; // Variable p of type pointer is pointing to the address of an integer array arr.

void show (int);
void(*p)(int) = &display; // Pointer p is pointing to the address of a function

struct st {
  int i;
  float f;
}ref;
struct st *p = &ref;

#include<stdio.h>
int main(){
int number=50; 
printf("value of number is %d, address of number is %u",number,&number);  
return 0;
}  

value of number is 50, address of number is fff4

int *p=NULL;

#include<stdio.h>
int main(){
int a=10,b=20,*p1=&a,*p2=&b;
printf("Before swap: *p1=%d *p2=%d",*p1,*p2);
*p1=*p1+*p2;
*p2=*p1-*p2;
*p1=*p1-*p2;
printf("\nAfter swap: *p1=%d *p2=%d",*p1,*p2);
return 0;
}

Before swap: *p1=10 *p2=20
After swap: *p1=20 *p2=10

int (*p)(int (*)[2], int (*)void))