两个矩阵相加的程序
#include <stdio.h> int main() { int r, c, a[100][100], b[100][100], sum[100][100], i, j; printf("Enter the number of rows (between 1 and 100): "); scanf("%d", &r); printf("Enter the number of columns (between 1 and 100): "); scanf("%d", &c); printf("\nEnter elements of 1st matrix:\n"); for (i = 0; i < r; ++i) for (j = 0; j < c; ++j) { printf("Enter element a%d%d: ", i + 1, j + 1); scanf("%d", &a[i][j]); } printf("Enter elements of 2nd matrix:\n"); for (i = 0; i < r; ++i) for (j = 0; j < c; ++j) { printf("Enter element b%d%d: ", i + 1, j + 1); scanf("%d", &b[i][j]); } // adding two matrices for (i = 0; i < r; ++i) for (j = 0; j < c; ++j) { sum[i][j] = a[i][j] + b[i][j]; } // printing the result printf("\nSum of two matrices: \n"); for (i = 0; i < r; ++i) for (j = 0; j < c; ++j) { printf("%d ", sum[i][j]); if (j == c-1) { printf("\n\n"); } } return 0; }
输出
Enter the number of rows (between 1 and 100): 2 Enter the number of columns (between 1 and 100): 3 Enter elements of 1st matrix: Enter element a11: 2 Enter element a12: 3 Enter element a13: 4 Enter element a21: 5 Enter element a22: 2 Enter element a23: 3 Enter elements of 2nd matrix: Enter element b11:-4 Enter element b12: 5 Enter element b13: 3 Enter element b21: 5 Enter element b22: 6 Enter element b23: 3 Sum of two matrices: -2 8 7 10 8 6
在这个程序中,要求用户输入行数
r
和列数
c
。然后,要求用户输入两个矩阵的元素(顺序为
rxc
)。
然后我们将两个矩阵的对应元素相加,并保存在另一个矩阵(二维数组)中。最后将结果打印在屏幕上。