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C 通过将矩阵传递给函数来将两个矩阵相乘的程序

通过将矩阵传递给函数来将两个矩阵相乘的 C 程序

在本例中,您将学习将两个矩阵相乘并使用用户定义的函数显示它。
要理解此示例,您应该了解以下C 编程 主题:
C 数组 C 多维数组 将数组传递给 C 中的函数
该程序要求用户输入矩阵的大小(行和列)。
然后,它要求用户输入这些矩阵的元素,最后添加并显示结果。
为了执行此任务,需要执行三个功能:
从用户获取矩阵元素enterData() 两个矩阵相乘multiplyMatrices() 显示乘法后的结果矩阵display()

示例: 通过将矩阵传递给函数来乘以矩阵

#include <stdio.h>
void enterData(int firstMatrix[][10], int secondMatrix[][10], int rowFirst, int columnFirst, int rowSecond, int columnSecond);
void multiplyMatrices(int firstMatrix[][10], int secondMatrix[][10], int multResult[][10], int rowFirst, int columnFirst, int rowSecond, int columnSecond);
void display(int mult[][10], int rowFirst, int columnSecond);
int main()
{
	int firstMatrix[10][10], secondMatrix[10][10], mult[10][10], rowFirst, columnFirst, rowSecond, columnSecond, i, j, k;
	printf("Enter rows and column for first matrix: ");
	scanf("%d %d", &rowFirst, &columnFirst);
	printf("Enter rows and column for second matrix: ");
	scanf("%d %d", &rowSecond, &columnSecond);
	// if colum of first matrix in not equal to row of second matrix, asking user to enter the size of matrix again.
	while (columnFirst != rowSecond)
	{
		printf("Error! column of first matrix not equal to row of second.\n");
		printf("Enter rows and column for first matrix: ");
		scanf("%d%d", &rowFirst, &columnFirst);
		printf("Enter rows and column for second matrix: ");
		scanf("%d%d", &rowSecond, &columnSecond);
	}
	// Function to take matrices data
        enterData(firstMatrix, secondMatrix, rowFirst, columnFirst, rowSecond, columnSecond);
        // Function to multiply two matrices.
        multiplyMatrices(firstMatrix, secondMatrix, mult, rowFirst, columnFirst, rowSecond, columnSecond);
        // Function to display resultant matrix after multiplication.
        display(mult, rowFirst, columnSecond);
	return 0;
}
void enterData(int firstMatrix[][10], int secondMatrix[][10], int rowFirst, int columnFirst, int rowSecond, int columnSecond)
{
	int i, j;
	printf("\nEnter elements of matrix 1:\n");
	for(i = 0; i < rowFirst; ++i)
	{
		for(j = 0; j < columnFirst; ++j)
		{
			printf("Enter elements a%d%d: ", i + 1, j + 1);
			scanf("%d", &firstMatrix[i][j]);
		}
	}
	printf("\nEnter elements of matrix 2:\n");
	for(i = 0; i < rowSecond; ++i)
	{
		for(j = 0; j < columnSecond; ++j)
		{
			printf("Enter elements b%d%d: ", i + 1, j + 1);
			scanf("%d", &secondMatrix[i][j]);
		}
	}
}
void multiplyMatrices(int firstMatrix[][10], int secondMatrix[][10], int mult[][10], int rowFirst, int columnFirst, int rowSecond, int columnSecond)
{
	int i, j, k;
	// Initializing elements of matrix mult to 0.
	for(i = 0; i < rowFirst; ++i)
	{
		for(j = 0; j < columnSecond; ++j)
		{
			mult[i][j] = 0;
		}
	}
	// Multiplying matrix firstMatrix and secondMatrix and storing in array mult.
	for(i = 0; i < rowFirst; ++i)
	{
		for(j = 0; j < columnSecond; ++j)
		{
			for(k=0; k<columnFirst; ++k)
			{
				mult[i][j] += firstMatrix[i][k] * secondMatrix[k][j];
			}
		}
	}
}
void display(int mult[][10], int rowFirst, int columnSecond)
{
	int i, j;
	printf("\nOutput Matrix:\n");
	for(i = 0; i < rowFirst; ++i)
	{
		for(j = 0; j < columnSecond; ++j)
		{
			printf("%d  ", mult[i][j]);
			if(j == columnSecond-1)
				printf("\n\n");
		}
	}
}
输出
Enter rows and column for first matrix: 3
2
Enter rows and column for second matrix: 3
2
Error! column of first matrix not equal to row of second.
Enter rows and column for first matrix: 2
3
Enter rows and column for second matrix: 3
2
Enter elements of matrix 1:
Enter elements a11: 3
Enter elements a12:-2
Enter elements a13: 5
Enter elements a21: 3
Enter elements a22: 0
Enter elements a23: 4
Enter elements of matrix 2:
Enter elements b11: 2
Enter elements b12: 3
Enter elements b21:-9
Enter elements b22: 0
Enter elements b31: 0
Enter elements b32: 4
Output Matrix:
24  29
6  25
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