该程序要求用户输入两个矩阵的大小(行和列)。
两个矩阵相乘，第一个矩阵的列数应该等于第二个矩阵的行数。
下面的程序要求两个矩阵的行数和列数，直到满足上述条件。
然后，执行两个矩阵的相乘，并将结果显示在屏幕上。
为此，我们创建了三个函数:
getMatrixElements()-获取用户输入的矩阵元素。
multiplyMatrices()-两个矩阵相乘。
display()-显示乘法后的结果矩阵。
通过将矩阵传递给函数来乘以矩阵
#include <stdio.h> // function to get matrix elements entered by the user void getMatrixElements(int matrix[][10], int row, int column) { printf("\nEnter elements: \n"); for (int i = 0; i < row; ++i) { for (int j = 0; j < column; ++j) { printf("Enter a%d%d: ", i + 1, j + 1); scanf("%d", &matrix[i][j]); } } } // function to multiply two matrices void multiplyMatrices(int first[][10], int second[][10], int result[][10], int r1, int c1, int r2, int c2) { // Initializing elements of matrix mult to 0. for (int i = 0; i < r1; ++i) { for (int j = 0; j < c2; ++j) { result[i][j] = 0; } } // Multiplying first and second matrices and storing it in result for (int i = 0; i < r1; ++i) { for (int j = 0; j < c2; ++j) { for (int k = 0; k < c1; ++k) { result[i][j] += first[i][k] * second[k][j]; } } } } // function to display the matrix void display(int result[][10], int row, int column) { printf("\nOutput Matrix:\n"); for (int i = 0; i < row; ++i) { for (int j = 0; j < column; ++j) { printf("%d ", result[i][j]); if (j == column-1) printf("\n"); } } } int main() { int first[10][10], second[10][10], result[10][10], r1, c1, r2, c2; printf("Enter rows and column for the first matrix: "); scanf("%d %d", &r1, &c1); printf("Enter rows and column for the second matrix: "); scanf("%d %d", &r2, &c2); // Taking input until // 1st matrix columns is not equal to 2nd matrix row while (c1 != r2) { printf("Error! Enter rows and columns again.\n"); printf("Enter rows and columns for the first matrix: "); scanf("%d%d", &r1, &c1); printf("Enter rows and columns for the second matrix: "); scanf("%d%d", &r2, &c2); } // get elements of the first matrix getMatrixElements(first, r1, c1); // get elements of the second matrix getMatrixElements(second, r2, c2); // multiply two matrices. multiplyMatrices(first, second, result, r1, c1, r2, c2); // display the result display(result, r1, c2); return 0; }
输出
Enter rows and column for the first matrix: 2 3 Enter rows and column for the second matrix: 3 2 Enter elements: Enter a11: 2 Enter a12:-3 Enter a13: 4 Enter a21: 53 Enter a22: 3 Enter a23: 5 Enter elements: Enter a11: 3 Enter a12: 3 Enter a21: 5 Enter a22: 0 Enter a31:-3 Enter a32: 4 Output Matrix: -21 22 159 179
