二进制转八进制程序
在这个程序中,我们将首先将二进制数转换为十进制数。然后,十进制数转换为八进制数。
#include <math.h> #include <stdio.h> int convert(long long bin); int main() { long long bin; printf("Enter a binary number: "); scanf("%lld", &bin); printf("%lld in binary = %d in octal", bin, convert(bin)); return 0; } int convert(long long bin) { int oct = 0, dec = 0, i = 0; // converting binary to decimal while (bin != 0) { dec += (bin % 10) * pow(2, i); ++i; bin /= 10; } i = 1; // converting to decimal to octal while (dec != 0) { oct += (dec % 8) * i; dec /= 8; i *= 10; } return oct; }
输出
Enter a binary number: 101001 101001 in binary = 51 in octal
八进制转二进制程序
在这个程序中,首先将一个八进制数转换为十进制数。然后,十进制数被转换为二进制数。
#include <math.h> #include <stdio.h> long long convert(int oct); int main() { int oct; printf("Enter an octal number: "); scanf("%d", &oct); printf("%d in octal = %lld in binary", oct, convert(oct)); return 0; } long long convert(int oct) { int dec = 0, i = 0; long long bin = 0; // converting octal to decimal while (oct != 0) { dec += (oct % 10) * pow(8, i); ++i; oct /= 10; } i = 1; // converting decimal to binary while (dec != 0) { bin += (dec % 2) * i; dec /= 2; i *= 10; } return bin; }
输出
Enter an octal number: 67 67 in octal = 110111 in binary