该程序要求用户存储
noOfRecords 的值，并使用
malloc() 动态地为
noOfRecords 结构变量分配内存功能。
演示结构的动态内存分配
#include <stdio.h> #include <stdlib.h> struct course { int marks; char subject[30]; }; int main() { struct course *ptr; int noOfRecords; printf("Enter the number of records: "); scanf("%d", &noOfRecords); // Memory allocation for noOfRecords structures ptr = (struct course *)malloc(noOfRecords * sizeof(struct course)); for (int i = 0; i < noOfRecords; ++i) { printf("Enter subject and marks:\n"); scanf("%s %d", (ptr + i)->subject, &(ptr + i)->marks); } printf("Displaying Information:\n"); for (int i = 0; i < noOfRecords; ++i) { printf("%s\t%d\n", (ptr + i)->subject, (ptr + i)->marks); } free(ptr); return 0; }
输出
Enter the number of records: 2 Enter subject and marks: Science 82 Enter subject and marks: DSA 73 Displaying Information: Science 82 DSA 73
