Statistics 可靠性系数
通过对同一个人进行两次测量并计算两组测量值的相关性而获得的测试或测量仪器准确性的测量值。
可靠性系数由以下函数定义和给出：
公式
${Reliability\ Coefficient,\ RC = (\frac{N}{(N-1)}) \times (\frac{(Total\ Variance\-Sum\ of\ Variance)}{Total Variance}) }$
哪里-
${N}$ = 任务数
示例
问题说明：
三个人 (P) 经历了一项事业，他们被分配了三个不同的任务 (T)。发现可靠性系数？
P0-T0 = 10
P1-T0 = 20
P0-T1 = 30
P1-T1 = 40
P0-T2 = 50
P1-T2 = 60
解决方案：
给定，学生数 (P) = 3 任务数 (N) = 3、要查找可靠性系数，请按照以下步骤操作：
步骤 1
给我们一个机会先算出每个人和他们的任务的平均分
The average score of Task (T0) = 10 + 20/2 = 15
The average score of Task (T1) = 30 + 40/2 = 35
The average score of Task (T2) = 50 + 60/2 = 55
步骤 2
接下来，计算方差：
Variance of P0-T0 and P1-T0:
Variance = square (10-15) + square (20-15)/2 = 25
Variance of P0-T1 and P1-T1:
Variance = square (30-35) + square (40-35)/2 = 25
Variance of P0-T2 and P1-T2:
Variance = square (50-55) + square (50-55)/2 = 25
步骤 3
现求P
0-T
0和P
1-T
0的个体方差， P
0-T
1 和 P
1-T
1, P
0-T
2 和 P
1-T
2。为了确定个体方差值，我们应该包括所有上述计算的变化值。
Total of Individual Variance = 25+25+25=75
步骤 4
计算总变化
Variance= square ((P0-T0)
-normal score of Person 0)
= square (10-15) = 25
Variance= square ((P1-T0)
-normal score of Person 0)
= square (20-15) = 25
Variance= square ((P0-T1)
-normal score of Person 1)
= square (30-35) = 25
Variance= square ((P1-T1)
-normal score of Person 1)
= square (40-35) = 25
Variance= square ((P0-T2)
-normal score of Person 2)
= square (50-55) = 25
Variance= square ((P1-T2)
-normal score of Person 2)
= square (60-55) = 25
现在，包括每一个品质并计算总的变化
Total Variance= 25+25+25+25+25+25 = 150
步骤 5
最后，代入下面提供的等式中的质量以发现
${Reliability\ Coefficient,\ RC = (\frac{N}{(N-1)}) \times (\frac{(Total\ Variance\-Sum\ of\ Variance)}{Total Variance}) \\[ 7pt] = \frac{3}{(3-1)} \times \frac{(150-75)}{150} \\[7pt] = 0.75 }$
